K = tga = f ' (a) = 0,5
f ' (x) = (sinx)' = cosx
f ' (pi/3) = cos (pi/3) = 1/2 = 0,5
- функция, которая задаёт прямую.
- функция, которая задаёт параболу.
Достаточно того, что бы эти точки лежали и на прямой и на параболе. Поэтому целесообразно составить две системы, которые получаются путём подстановки абсцисс и ординат точек пересечения в исходные функции. Точки пересечения A(-4;4) и B(-6; 10).
![\begin{cases}4 = -4k + l\\ 10 = -6k + l\end{cases}\\\\ \begin{cases} 4 + 4k = l\\ 10 = -6k + l\end{cases}\\\\ \begin{cases} 4 + 4k = l\\ 10 = -6k + 4 + 4k\end{cases}\\\\ \begin{cases} 4 + 4k = l\\ 6 = -2k \end{cases}\\\\ \begin{cases} 4 + 4(-3) = l\\ k = -3\end{cases}\\\\ \begin{cases} l = -8\\ k = -3 \end{cases}\\\\ y = -3x - 8](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D4+%3D+-4k+%2B+l%5C%5C+10+%3D+-6k+%2B+l%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+4+%2B+4k+%3D+l%5C%5C+10+%3D+-6k+%2B+l%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+4+%2B+4k+%3D+l%5C%5C+10+%3D+-6k+%2B+4+%2B+4k%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+4+%2B+4k+%3D+l%5C%5C+6+%3D+-2k+%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+4+%2B+4%28-3%29+%3D+l%5C%5C+k+%3D+-3%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+l+%3D+-8%5C%5C+k+%3D+-3+%5Cend%7Bcases%7D%5C%5C%5C%5C+y+%3D+-3x+-+8)
![\begin{cases} 4 = 16 - 4b + c\\ 10 = 36 - 6b + c \end{cases}\\\\ \begin{cases} -12 + 4b = c\\ 10 = 36 - 6b - 12 + 4b \end{cases}\\\\ \begin{cases} -12 + 4b = c\\ -14 =-2b \end{cases}\\\\ \begin{cases} -12 + 4*7 = c\\ b = 7 \end{cases}\\\\ \begin{cases} c = 16\\ b = 7 \end{cases}\\\\ y = x^2 + 7x + 16](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D+4+%3D+16+-+4b+%2B+c%5C%5C+10+%3D+36+-+6b+%2B+c+%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+-12+%2B+4b+%3D+c%5C%5C+10+%3D+36+-+6b+-+12+%2B+4b+%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+-12+%2B+4b+%3D+c%5C%5C+-14+%3D-2b+%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+-12+%2B+4%2A7+%3D+c%5C%5C+b+%3D+7+%5Cend%7Bcases%7D%5C%5C%5C%5C+%5Cbegin%7Bcases%7D+c+%3D+16%5C%5C+b+%3D+7+%5Cend%7Bcases%7D%5C%5C%5C%5C+y+%3D+x%5E2+%2B+7x+%2B+16)
![\fbox{k = -3, l = -8, b = 7, c = 16}](https://tex.z-dn.net/?f=+%5Cfbox%7Bk+%3D+-3%2C+l+%3D+-8%2C+b+%3D+7%2C+c+%3D+16%7D)
<span>Найдите четыре первые члена последовательности (an)
1)an=5-n
а</span>₁ = 5 - 1= 4; а₂ = 5 - 2 = 3; а₃ - 5 - 3 = 2; а₄= 5 - 4 = 1.<span>
2)an= (n^2 +1)/n
а</span>₁ = (1 +1)/2 = 2;
а₂ = (2²+1)/2 =5/2 = 2,5;
а₃ = (3² +1)/3 = 10/3;
.а₄= (4² +1)/4= 17/4
4x+5y-4, при х=3 и у=6: 12+30-4=28