1)1/a-1/(b+c)=(b+c-a)/[a(b+c)]
2)1/a+1/(b+c)=(b+c+a)/[a(b+c)]
3)(b+c-a)/[a(b+c)] :(b+c+a)/[a(b+c)]=(b+c-a)/(b+c+a)
a=0,01;b=8,21;c=1,78
<span>(8,21+1,78-0,01)/(8,21+1,78+0,01)=9,98/10=0,998
</span>
4√3=√16*√3=√48
3√5=√9*√5=√45
7=√49
√45<√48<√49
Ответ: 3√5 4√3 7