2*0,545³+2*0,455³=2[(0.545+0.455)(0.545²-0.545*0.455+0.455²]=
2*1*(0.545²+0.455²)
2(0.545²+0.455²)-3(0.545²+0.455²)=-(0.545²+0.455²)= - (0.297025+0.207025)= - 0.50405
Запишем
A(ω)<=1.8Α(0)=Α(0)*ω(ρ)^2/mod[ω(ρ)^2-ω^2]
Решим относительно ω
1.8Α(0)=Α(0)*ω(ρ)^2/mod[ω(ρ)^2-ω^2]
1.8Α(0)*ω(ρ)^2-1.8Α(0)*ω^2=Α(0)*ω(ρ)^2
0.8Α(0)*ω(ρ)^2=1.8Α(0)*ω^2
4Α(0)*ω(ρ)^2=9Α(0)*ω^2--->ω=(2/3)*ω(ρ)=2*300/3=200 c^(-1)<ω(ρ)
ω=200 c^(-1)