<span>(1,6х+1)(1-1,6х)-64х(1-0,04х)=0
1,6х-2,56х²+1-1,6х-64х+2,56х²=0
</span><span>1-64х=0</span>
-64х=-1
х=1/64
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Вектор AB(-3;-8;3);
Вектор AB = -3i-8j+3k.
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Решение:
( х + 1) ³ = х²·( х +1 )
( х + 1) ³ - х²·( х +1 ) = 0
( х + 1) · ( ( х +1 )² - х²) = 0
( х + 1) · ( х² +1² + 2х - х²) = 0
( х + 1) · (1 + 2х ) = 0
х + 1= 0 или 1 + 2х = 0
х + 1 = 0 2х = -1
х = -1 х = -0,5
Ответ: -1 ; - 0,5.
А) 15a-3a+11a+5a-12a=16a
b) 3m-4n+5m+3n+n-7m=m