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![0.5(8x-3)=-5(2.5-x) \\ 4x-1.5=-1+4x \\ 0x=2.5 \\](https://tex.z-dn.net/?f=0.5%288x-3%29%3D-5%282.5-x%29+%5C%5C+4x-1.5%3D-1%2B4x+%5C%5C+0x%3D2.5+%5C%5C+)
Ответ: <em>нет решений </em>
Очень простое квадратное уравнение, где изначально нужно избавиться от 6 в знаменателе.
![\frac{ x^{2} -x}{6}=2\\ \frac{ x^{2} -x}{6}= \frac{12}{6} \\ x^{2} -x=12\\ x^{2} -x-12=0\\ D=b^{2}-4*a*c=1-4*(-12)*1=1+48=49\\ x1= \frac{-b+ \sqrt{D} }{2a} = \frac{1+7}{2}=4\\ x2= \frac{-b-\sqrt{D} }{2a} = \frac{1-7}{2}=-3\\](https://tex.z-dn.net/?f=+%5Cfrac%7B+x%5E%7B2%7D+-x%7D%7B6%7D%3D2%5C%5C%0A+%5Cfrac%7B+x%5E%7B2%7D+-x%7D%7B6%7D%3D+%5Cfrac%7B12%7D%7B6%7D+%5C%5C%0A+x%5E%7B2%7D+-x%3D12%5C%5C%0A+x%5E%7B2%7D+-x-12%3D0%5C%5C%0AD%3Db%5E%7B2%7D-4%2Aa%2Ac%3D1-4%2A%28-12%29%2A1%3D1%2B48%3D49%5C%5C%0Ax1%3D+%5Cfrac%7B-b%2B+%5Csqrt%7BD%7D+%7D%7B2a%7D+%3D+%5Cfrac%7B1%2B7%7D%7B2%7D%3D4%5C%5C%0Ax2%3D+%5Cfrac%7B-b-%5Csqrt%7BD%7D+%7D%7B2a%7D+%3D+%5Cfrac%7B1-7%7D%7B2%7D%3D-3%5C%5C)
Ответ: x1=4; x2=-3;
7x^3-63x=0
7x(x^2-9)=0
7x=0 или x^2-9=0
x=0 x^2=9
x=3
<span>Ответ:0,3
Спасибо нажми :-)</span>