А. 4х^4*(-2х^2)^3=2х^8*(-2х^6)=-(2х^14)
б.(3х-1)(3х+1)+(3х+1)^2=9х^2+3х-3х-1+9х^2+1=9х^4
Решаем как квадрaтное ( arctgx = z)
D = 25- 16 = 9
arctgx = (5+3)/4 = 2 arctgx = (5-3)/4 = 1/2
-π/2 < arctg x < π/2, ⇒ arctg x = 1/2
F(x)=3.x³-2x²-4
F´(x)=3.3.x²-2.2.x=9x²-4x
F´(-1)=9.(-1)²-4.(-1)=9.1+4=9+4=13
k=13