![- 3 x = - 2 \\ x = \frac{ - 2}{ - 3} \\ x = \frac{2}{3}](https://tex.z-dn.net/?f=+-+3+x+%3D++-+2+%5C%5C+x+%3D+++%5Cfrac%7B+-+2%7D%7B+-+3%7D++%5C%5C+x+%3D++%5Cfrac%7B2%7D%7B3%7D+)
![5x = 0 \\ x = \frac{0}{5} \\ x = 0](https://tex.z-dn.net/?f=5x+%3D+0+%5C%5C+x+%3D++%5Cfrac%7B0%7D%7B5%7D++%5C%5C+x+%3D+0)
![0 \times x = 0](https://tex.z-dn.net/?f=0+%5Ctimes+x+%3D+0+)
х - любое число, т.к при умножении любого числа на ноль будет ноль
![6x - 13 = 3x + 10 \\ 6x - 3x = 10 + 13 \\ 3x = 23 \\ x = \frac{23}{3} \\ x = 7 \frac{2}{3}](https://tex.z-dn.net/?f=6x+-+13+%3D+3x+%2B+10+%5C%5C+6x+-+3x+%3D+10+%2B+13+%5C%5C+3x+%3D+23+%5C%5C+x+%3D++%5Cfrac%7B23%7D%7B3%7D++%5C%5C+x+%3D+7+%5Cfrac%7B2%7D%7B3%7D+)
![5-2x=11-7(x+2)](https://tex.z-dn.net/?f=5-2x%3D11-7%28x%2B2%29)
![5-2x=11-7x-14](https://tex.z-dn.net/?f=5-2x%3D11-7x-14)
![5-2x=-3-7x](https://tex.z-dn.net/?f=5-2x%3D-3-7x)
![7x-2x=-3-5](https://tex.z-dn.net/?f=7x-2x%3D-3-5)
![5x=-8](https://tex.z-dn.net/?f=5x%3D-8)
![x=-8:5](https://tex.z-dn.net/?f=x%3D-8%3A5)
![x=-\frac{8}{5}=-1,6](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B8%7D%7B5%7D%3D-1%2C6)
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(это проверка)
![5+3,2=11-7\cdot0,4](https://tex.z-dn.net/?f=5%2B3%2C2%3D11-7%5Ccdot0%2C4)
![8,2=11-2,8](https://tex.z-dn.net/?f=8%2C2%3D11-2%2C8)
![8,2=8,2](https://tex.z-dn.net/?f=8%2C2%3D8%2C2)
<span>f(x)=1/3x^3+2x-2</span>
Надо найти f' и приравнять 0, найдем точки экстремума
f' = 3*1/3 *x^2 +2 = x^2+2 >0 при любых x, значит, точек экстремума, в том числе и т. максимума, у этой функции нет
Х=4:
12-32=-20
х=-2
12+16=28
х=0
12
х=3/8
хм... 9?
насчёт последнего не уверена