<span>5х-9(2+х)<-8х-6
5x-18-9x<-8x-6
4x<12
x<3 x∈(-∞;3)
9х-5(-7+4х)<-9х+10
9x+35-20x<-9x+10
2x>25
x>12.5 x∈(12.5;+∞)</span>
6c³ - 48 = 6( c³ - 8 ) = 6 ( c - 2 )( c² + 2c + 4)
Вопроса не поняла, но вот корни уравнения:(х-1)(х+2)=10x^2+2x-x-2=10
x^2+x-2=10
x^2+x-12=0
x1+x2=-1
x1*x2=-12
x1=-4
x2=3
Ответ:x=-4,x=3
<span>х-(50-х)=12</span>
х-50+х=12
х+х=12+50
2х=62/2
х=31
2.<span>х+(х+1)+(х+2)=9</span>
<span>х+х+1+х+2=9</span>
<span>3х=-1+9</span>
<span>3х=8/3</span>
<span>х=3/8</span>
<span>3.</span>