Question

Не могу решить,плиз!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$\sqrt[3]{x} +2 \sqrt[3]{ x^{2} -3} =0 \\ \sqrt[3]{x} =-2 \sqrt[3]{ x^{2} -3} \\ (\sqrt[3]{x}) ^{3} =(-2 \sqrt[3]{ x^{2} -3}) ^{3} \\ x=-8(x^{2} -3) \\ x=-8 x^{2} +24 \\ 8 x^{2} +x-24=0 \\ D=1+768=769 \\ x= \frac{-1+ \sqrt{769} }{16} \\ x= \frac{-1- \sqrt{769} }{16} \\ OTBET: \frac{-1- \sqrt{769} }{16} ; \frac{-1+ \sqrt{769} }{16}$