√13^2-12^2=√(13-12)(13+12)=√1*25=5
![4 x^{2} -12x+9 \leq 0 \\ 4 x^{2} -12x+9=0 \\ D=144-144=0 \\ x_{0} = \frac{12}{8} =1.5 \\ x-1.5 \leq 0 \\ \\ \\](https://tex.z-dn.net/?f=4+x%5E%7B2%7D+-12x%2B9+%5Cleq+0+%5C%5C+4+x%5E%7B2%7D+-12x%2B9%3D0+%5C%5C+D%3D144-144%3D0+%5C%5C++x_%7B0%7D+%3D+%5Cfrac%7B12%7D%7B8%7D+%3D1.5+%5C%5C+x-1.5+%5Cleq+0+%5C%5C++%5C%5C++%5C%5C+)
- +
------------------------|-------------------------------------->
1.5
![x\in (- \infty ;1.5]](https://tex.z-dn.net/?f=+x%5Cin+%28-+%5Cinfty+%3B1.5%5D+)
у= кх -3 вместо х подставляем -2, вместо у 9. к=-6
Х=0/-10
х=0
ответ:х равен нулю
sin(3x-π )=√3/2. -sin(π-3x)=√3/2. - sin3x=√3/2. sin3x=-√3/2
3x=(-1)^n arcsin(-√3/2)+πn.n∈Z
3x=(-1)^(n+1)π/3 +πn
x= (-1)^(n+1) π/9 +πn/3. n∈Z