Ответ:
-п/4
Объяснение:
1+cos2x=1+2sin2xcos2x
2cos2xsin2x-cos2x=0
cos2x=0 2x=П/2+Пk x=п/4+Пk/2 k=-1 П/4-п/2=-П/4
2sin2x=1 sin2x=1/2 2x=(-1)^kП/6+Пk
x=(-1)^kП/12+Пk/2 k=-1
x=-П/12-П/2
(х-1)(х+1)(х^2+1)(х^4+1)=х^8-1
(х^2-1)(х^2+1)(х^4+1) = (х^4-1)(х^4+1) = х^8-1
х^8-1 = х^8 - 1
An = A1 + (n - 1)D;
A1 = An - (n - 1)D;
A1 = 38 - (15 - 1)*3 = 38 - 14*3 = 38 - 42 = -4;
Sn = n*(2A1 + D(n-1))/2
S10 = 10*(2*(-4) + 3(10-1))/2 = 10*(-8 + 27)/2 = 5*19 = 95;