Question

Помогите пожайлуста.
³√(3x²-3)=³√8x

Answer 1

$\sqrt[3]{(3x^2-3)} = \sqrt[3]{(8x)} \\ \\ (3x^2-3)=(8x) \\ \\ 3x^2-8x-3=0 \\ D=b^2-4ac=(-8)^2-4*3*(-3)=64+36=100 \\ \\ x_{1} = \frac{-b+ \sqrt{D} }{2a} = \frac{8+10}{6} = \frac{18}{6} =3 \\ \\ x_{2} = \frac{-b- \sqrt{D} }{2a} = \frac{8-10}{6} = \frac{-2}{6} = -\frac{1}{3}$