(x - 1)³ - x²(x - 1) = 0
x³ - 3x² + 3x - 1 - x³ + x² = 0
- 2x² + 3x - 1 = 0
2x² - 3x + 1 = 0
D = 1
x1 = (3 + 1)/4 = 1
x2 = (3 - 1)/4 = 0.5
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Икс выносим за скобки
х(3-х)=0
теперь эти два множителя приравниваем нулю
х=0
(3-х)=0
-3=-х
х=3
Ответ:3 и 0
F=x-sinx+C.....................................