Question

X⁴-13x²-12x=0 помогите пожалуйста срочно

Answer 1

​x​4​​−13x​2​​−12x=0​
x(x​3​​−x−12x−12)=0​
x(x(x​2​​−1)−12(x−1))=0​
x(x(x−1)(x+1)−12(x+1))=0
​x(x+1)(x​2​​−x−12)=0
​x(x+1)(x​2​​+3x−4x−12)=0​
x(x+1)(x(x+3)−4(x+3))=0​
x(x+1)(x+3)(x−4)=0​
x=0, x=−1, x=−3, x=4​​ 

Answer 2

$x^4-13x^2-12x=0 \\ x(x^3-x-12x-12)=0 \\ x(x(x^2-1)-12(x-1))=0 \\ x(x(x-1)(x+1)-12(x+1))=0 \\ x(x+1)(x^2-x-12)=0 \\ x(x+1)(x^2+3x-4x-12)=0 \\ x(x+1)(x(x+3)-4(x+3))=0 \\ x(x+1)(x+3)(x-4)=0 \\ x=0, \ x=-1, \ x=-3, \ x=4$

Ответ: -3; -1; 0; 4