A) f`(x)=-sin(x-π/6)
б) f`(x)=-cos(π/4-x)
b)f`(x)=-1/(sin²(π/6+x))
г)f`(x)=1/cos²(x+π/3)
А)<span> 3(1+2xy)(1-2xy)=3(1-2ху+2ху-4х^2y^2)=3-12x^2y^2(^2-это в квадрате)
б)(х^2-y^3)=x^4-2x^4y^6+y^6
в)(a+b)^2-(a-b)^2=a^2+2ab+b^2-(</span><span>a^2-2ab+b^2)=a^2+2ab+b^2-a^2+2ab-b^2=4ab </span>
2p - (3p - 2p + c)= 2p - 3p +2p - c= -3p-c
9+13х=35+26х
13х-26х=35-9
-13х=26
<span>х=-2</span>