А)4х-3х=1 х=1. Б)-х=-13-5 х=18 в)7х+х-6х=8+2 2х=9 х=4.5
Решение во вложении на фото:
![\dfrac{ \sqrt[3]{a^2\cdot \sqrt[4]{a^6\cdot a^{-1}} } }{\sqrt[4]{a^3\cdot \sqrt[3]{a^2} }} =\dfrac{ \sqrt[3]{a^2\cdot \sqrt[4]{a^{6-1}} } }{\sqrt[4]{a^3\cdot a^{\frac{2}{3}} }} =\dfrac{ \sqrt[3]{a^2\cdot a^{\frac{5}{4}} } }{\sqrt[4]{a^3\cdot a^{\frac{2}{3}} }} =\dfrac{ \sqrt[3]{a^{2+ \frac{5}{4} }} }{ \sqrt[4]{a^{3+ \frac{2}{3} }} }= \dfrac{ \sqrt[3]{a^{\frac{13}{4}}} }{ \sqrt[4]{a^{\frac{11}{3}}} } =\\\\\\=\dfrac{a^{\frac{13}{12}}}{a^{\frac{11}{12}}}=a^{\frac{13}{12}-\frac{11}{12}}=a^{\frac{1}{6}}](https://tex.z-dn.net/?f=+%5Cdfrac%7B+%5Csqrt%5B3%5D%7Ba%5E2%5Ccdot+%5Csqrt%5B4%5D%7Ba%5E6%5Ccdot+a%5E%7B-1%7D%7D+%7D+%7D%7B%5Csqrt%5B4%5D%7Ba%5E3%5Ccdot+%5Csqrt%5B3%5D%7Ba%5E2%7D+%7D%7D+%3D%5Cdfrac%7B+%5Csqrt%5B3%5D%7Ba%5E2%5Ccdot+%5Csqrt%5B4%5D%7Ba%5E%7B6-1%7D%7D+%7D+%7D%7B%5Csqrt%5B4%5D%7Ba%5E3%5Ccdot+a%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D+%7D%7D+%3D%5Cdfrac%7B+%5Csqrt%5B3%5D%7Ba%5E2%5Ccdot+a%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D+%7D+%7D%7B%5Csqrt%5B4%5D%7Ba%5E3%5Ccdot+a%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D+%7D%7D+%3D%5Cdfrac%7B+%5Csqrt%5B3%5D%7Ba%5E%7B2%2B+%5Cfrac%7B5%7D%7B4%7D+%7D%7D+%7D%7B+%5Csqrt%5B4%5D%7Ba%5E%7B3%2B+%5Cfrac%7B2%7D%7B3%7D+%7D%7D+%7D%3D+%5Cdfrac%7B+%5Csqrt%5B3%5D%7Ba%5E%7B%5Cfrac%7B13%7D%7B4%7D%7D%7D+%7D%7B+%5Csqrt%5B4%5D%7Ba%5E%7B%5Cfrac%7B11%7D%7B3%7D%7D%7D+%7D+%3D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7Ba%5E%7B%5Cfrac%7B13%7D%7B12%7D%7D%7D%7Ba%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D%7D%3Da%5E%7B%5Cfrac%7B13%7D%7B12%7D-%5Cfrac%7B11%7D%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
если все верно сделала, то ответ 1)
<em>f(x) = 2x - 5</em>
а) f(0) = 2·0 - 5 = -5
f(-1,5) = 2·(-1,5) - 5 = -3 - 5 = -8
б) f(x) = 18
2x - 5 = 18; 2x = 23; x = 11,5
f(x) = 0
2x - 5 = 0; 2x = 5; x = 2,5
5с+10=5(с+2)....................