<span> 3m-6n+mn-2n^2=3(m-2n)+n(m-2n)=(m-2n)(3+n)</span>
Х³-х=0
х(х²-1)=0
х=0
или
х²-1=0
х²=1
х=1; х=-1
ответ: -1; 0; 1
х²-24х+144=0
(х-12)²=0
х-12=0
х=12
ответ: 12
25у²-49=0
25у²=49
у²=49/25
у=7/5; у=-7/5
ответ: -7/5; 7/5
(х+4у)/у=10
х+4у=10*у
х=10у-4у =6у
(7х-у)/х =(7*6у -у)/6у= (42у-у)/6у =41/6
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![|5-x| + |8-x|](https://tex.z-dn.net/?f=%7C5-x%7C+%2B+%7C8-x%7C)
![6\leq x \leq 7](https://tex.z-dn.net/?f=6%5Cleq+x+%5Cleq+7)
![x+5+8-x=13](https://tex.z-dn.net/?f=x%2B5%2B8-x%3D13)
Согласно условию раскрытия модуля:
![|x|=\left \{ {{x, x\geq 0} \atop {-x, x<0}} \right.](https://tex.z-dn.net/?f=%7Cx%7C%3D%5Cleft+%5C%7B+%7B%7Bx%2C+x%5Cgeq+0%7D+%5Catop+%7B-x%2C+x%3C0%7D%7D+%5Cright.)
Ответ: 13