Question

2cos300-ctg315= Помогите решить!

Answer 1

$2cos300-ctg315=2cos(360-60)-ctg(360-45)= \\ =2cos(2 \pi -60)-ctg(2 \pi -45)=2cos60-ctg(-45)= \\ =2* \frac{1}{2} -(-1)=1+1=2$

Answer 2

$2cos300-ctg315=2cos(360-60)-ctg(360-45)=\\\\=2cos60-ctg(-45)=2cos60+ctg45=2\cdot \frac{1}{2}+1=2$