B7=b1×q^8
b7=-24×1/256=-24/256=-3/32
(ab-b^2-a^2-ab\ab)*(b^2*a^2\b^2+a^2)=(-(a^2+b^2)\ab)*(b^2*a^2\b^2+a^2)=-ab
Log₂<span> ( x -3 ) > 4 ОДЗ: х - 3 > 0 </span>→ x > 3<span>
</span>log₂ ( x -3 ) > <span>log</span>₂<span> 16
х - 3 > 16
x > 19
Ответ: х </span>∈ (19; +∞)<span>
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