1) 12-2x/x-2+10-x/2-x=12-2x/x-2+10-x/-(x-2)=12-2x/x-2-10-x/-(x-2)=12-2x-(10-x)/x-2=12-2x-10+x/x-2=2-x/x-2=-(x-2)/x-2=-1
Ответ: -1
1)3(1-4x^2y^2) так как в скобках разность квадратов
3-12x^2y^2
2)(x^2-y^2)^2=((x-y)(x+y))^2=(x^2-2xy+y^2)(x^2+2xy+y^2)= x^4+2x^3y+2x^2y^2-4x^2y^2-2xy^2+x^2y^2+2xy^3+y^4= x^4+2x^y-1x^2y^2+y^4
у' = (-8x + 45)' = -8 +0 = -8
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1) 2
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2a²b
2) 3
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x+4
3) y-z
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2
3*(x^2+8*x+16)-10*x-32=0
3*x^2+24*x+48-10*x-32=0
3*x^2+14*x+16=0
D=14^2 - 4 * 3 * 16 = 4
x1 = (-14-2) / 3*2 = -2 2/3
<span>x2 = (-14+2) / 3*2 = -2</span>