(3x+2y)(3x+2y)(4x-8y)(4x+8y)=
=(3x+2y)^2 (16x^2-64y^2)
(x-2)/(x²+3x-10)=(x-2)/(x-2)(x+5)=(скокращаем x-2)=1/(x+5)
D=9+40=49
x12=(-3+-7)/2=2 -5
(x+1)/(4x²+x-3)=(x+1)/(x+1)(4x-3)=1/(4x-3)
D=1+48=49
x12=(-1+-7)/8=-1 3/4
Область определения: х> 1;2 дробь