Question

Решить уравнение! 1) 3х(х-2)=4х+7

Answer 1

$\\3x^{2}-6x=4x+7\\ 3x^{2}-10x-7=0\\ D=10^{2}-4\cdot3\cdot(-7)=184=(2\sqrt{46})^{2}\\ x_{1}=\frac{10-2\sqrt{46}}{6}=\frac{5-\sqrt{46}}3}\\ x_{2}=\frac{5+\sqrt{46}}{3}$

Answer 2

$3x(x-2)=4x+7\\3x^2-6x=4x+7\\3x^2-10x-7=0\\D=100-4\cdot(-21)=100+84=184=2\sqrt{46}\\x_1=\frac{10+2\sqrt{46}}{2*3}=\frac{2(5+\sqrt46)}{6}=\frac{5+\sqrt46}{3}\\x_2=\frac{10-2\sqrt46}{6}=\frac{2(5-\sqrt46)}{6}=\frac{5-\sqrt46}{3}$