Question

3а^2+а=4;как решить?​

Answer 1

3а^2+а-4=0

D=1+48=49

X= -1±7/6

X1=-1+7/6=1

X2=-1-7/6=-8/6=-4/3=-1 1/3

Answer 2

3a²+a-4=0

d=b²-4ac= 1-4*3*(-4)=49

x1x2=-b±√d/2a

X= -4/3

X=1