Question

Найдите корни уравнений: x^3 - 3x^2 + 2x =0

Answer 1

X^{3} -3 x^{2} +2x=0
x^{3} - x^{2}-2x^{2}  +2x=0
x^{2} (x-1)-2x(x-1)=0
(x-1)(x^{2}-2x)=0
(x-1)(x-2)x=0
x-1=0 => x=1
x-2=0 => x=2
x=0

Answer 2

X^3 - 3x^2 + 2x = 0
x(x^2 - 3x +2 ) = 0
x^2 - 3x+2 = 0              x=0
Д=9-8=1
x1= (3+1)/2=2
x2=(3-1)/2= 1
Ответ:x=0, x=1, x=2