У нас есть 8√2(сos²x-sin²x) x=Π/8
cos²x-sin²x=cos2x
8√2*cosΠ/4=8√2*(√2/2)=8
(3x²-9yx)/(x²-9y²)=3x(x-3y)/((x-3)(x+3))=3x/(x+3).
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(3а – 5) + (2а – 4) – (5а - 2)=3а – 5 + 2а – 4 – 5а + 2=5а – 5 – 4 – 5а + 2=<span>– 5 – 4 + 2=-7
</span>4(3а - 3) – 5 (4а + 4) + 8а =12а - 12 – 20а -20 + 8а =20а - 12 – 20а -20 = - 12 -20<span> =-32</span>