Question

Lim стремится к 3 (x^2-2x-3)/(x^2-5x+6)

Answer 1

$\lim_{x \to 3} \frac{x^2-2x-3}{x^2-5x+6} = \lim_{x \to 3} \frac{(x-3)(x+1)}{(x-3)(x-2)} = \\ = \lim_{x \to 3} \frac{x+1}{x-2} = 4$