Question

Найти область определения функции;

Answer 1

$y=\frac{\sqrt{x}}{x-4}\\\\OOF:\; \left \{ {{x \geq 0} \atop {x-4\ne 0}} \right. \; \left \{ {{x \geq 0} \atop {x\ne 4}} \right. \; \to \; \; x\in [0,4)U(4,+\infty)\\\\\\y=\sqrt{5x-17}+\sqrt{22-8x}\\\\OOF:\; \left \{ {{5x-17 \geq 0} \atop {22-8x \geq 0}} \right. \; \left \{ {{x \geq \frac{17}{5}} \atop {x \leq \frac{22}{8}}} \right. \; \left \{ {{x \geq 3,4} \atop {x \leq 2,75}} \right. \; \; \to \; \; x\in \varnothing,\;pystomy \; mnozestvy$