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1). 9,885-0,365=9,52
2). 9,52:1,7=5,6
3). 5,6+4,4=10
1) =(sinb/cosb+1)/(cosb/sinb+1)= (sinb+cosb)/cosb):(sinb+cos b)/sinb=
=(sinb+cosb)/cosb)*(sinb/(sinb+cosb)=sinb/cosb=tgb
2) =²a+2sinacosa+cos²a-2sina* cosa=sin²a+cos²a=1
3)=(sin²a+cos²a)²=1
4) =2-(sin²a+cos²a)/3(sin²a+cos²a)=2-1/3*1=1/3
5) = (sin²a-cos²a)(sin²a+cos²a)/sin²a-cos²a)=sin²a+cos²a=1
2(2х-4)-5<=14х+37
4х-8-5-14х-37<=0
-10х<=50
10х>=-50
х>=-5
решение: х принадлежит [-5;бесконечность)
