sinx-cosx=0 или 1+2cosx=0
sinx=cosx |:cosx≠0 2cosx=-1
tgx=1 cosx=-1/2
x=π/4+πn; n∈z x=+-2π/3+2πn; n∈z
Ответ: <span>
π/4+πn; n∈z +-2π/3+2πn; n∈z</span>
(8x-1)(8x+1)-(16x-3)(4x+1)=64x^2-1-(64x^2+16x-12x-3)=<span>64x^2-1-64x^2-16x+12x+3=28x+2</span><span>
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