B*ab+a^2b=b^2+a^2b=ab(b+a)
<span>y=-0,5x^2+2,5 и y=2x^2+x
0.5x</span>²+2.5=2x²+x
1.5x²+x-2.5=0 3x²+2x-5=0 √D=√4+60=8
x1=1/6[-2-8] = -10/6=-5/3 x2=1/6[-2+8] =1
<span>lg²x+lgx²=3
</span><span>lg²x + 2lgx - 3 = 0
lgx = z
z</span>² + 2z - 3 = 0
z₁ = - 3
z₂ = 1
<span>1) lgx = - 3
x = 10^(-3)
x</span>₁ = 0,001
2) lgx = 1
x₂ = 10
Ответ: b) <span>0,001;10</span>
Решение
(4а-1/3х)•(-3х) = <span>(4a)*(-3x) - (1/3х)•(-3х) = - 12ax + 1</span>