Question

Решите уравнение сos (x+п/6) = - корень 3/2 tg 3x = корень 3

Answer 1

Cos(x+π/6)=-√3/2
x+π/6=-5π/6+2πk U x+π/6=5π/6+2πk
x=-π+2πk U x=2π/3+2πk,k∈z

tg3x=√3
3x=π/3+πk
x=π/9+πk/3,k∈z