Решение
x² + px + q = 0
По теореме Виета
x₁ + x₂ = - p; x₁ * x₂ = q
- 5 + 8 = 3
p = - 3
- 5*8 = - 40
q = - 40
x² - 3x - 40 = 0
-x^2-4x-4=-x^2+6x-9
-10x=-5
x=1/2
8m³+27=(2m)³+3³=(2m+3)(4m²-6m+9)
6m²+13m+6
D=13²-4*6*6=169-144=25
√D=5
m₁=(-13-5)/12=-18/12=-3/2
m₂=(-13+5)/12=-8/12=-2/3
6m²+13m+6=6(m+3/2)(m+2/3)=(2m+3)(3m+2)