<span>8а²+28а-16
a=0 8*0+28*0-16=-16</span>
B5=b1*q^4=4
b9=b1*q^8=1/4
q^4=0,0625
q=+-0/5
√<span>3 sin 3x=cos 3 x /(</span>√3)*<span>cos3x </span>≠ 0
tg(3x) = 1/√3
3x = arctg(1/√3) + πn, n∈Z
3x = π/6 + πn, n∈Z
x = π/18 + (πn)/3, n∈Z
√x=4/x графическое решение приложено x=2.6 y=1.6
<u />(2-а)/(b+c)= (2-5,5) / ( 4,7+1,9)= - 3,5/6,6 = -0,53