Kn^2-n^2-kn+n=74
n^2(k-1)-n(k-1)=74
(n^2-n)(k-1)=74
n(n-1)(k-1)=74
74=1*2*37, а т.к. n и n-1 последовательные натуральные числа, то n=2, n-1=1, тогда k-1=37, k=38.
Ответ: n=2, k=38
3X^2+6x-x-2-20=0 3x^2+5x-22=0 D=25+264=289 x1=-5+17/2*3=12/6=2 X2=-5-17/2*3=-22/6 =-3,667
Log3log8log2 (x-5) = log3(2) -1
log3log8log2 (x-5) = log3(2) - log3(3)
log3log8log2 (x-5) = log3(2/3)
log8log2 (x-5) = 2/3
log8log2 (x-5) = log8 (8^(2/3))
log8log2 (x-5) = log8(4)
log2 (x-5) = 4
log2 (x-5) = log2(2^4)
log2 (x-5) = log2(16)
x-5 =16
x=21
Проверка
log3log8log2 (21-5) = log3log8log2(16) = log3log8(4) = log3(2/3) = log3(2)-1
Ответ:21
решение во вложении.....................................................................................................................................................................................................................................................
1)х^2-x-x^2+2x-9=x-9
2)9a^2+27a+a^4+3a^3-3a^3-9a^2=a^4+27a
