Question

Выполните действия!!!!!! 4y^2-1 / y^2-9 : 6y+3/ y+3

Answer 1

1)4y²-1
(2y-1)*(2y+1)
2)---
3)---

Answer 2

$\frac{4y^2 - 1}{y^2 - 9} : \frac{6y + 3}{y + 3} = \frac{(2y - 1)(2y + 1)}{(y - 3)(y + 3)} * \frac{y + 3}{3 (2y + 1)} = \frac{2y - 1}{3 (y - 3)}$