<span>CH3-CH=CH-CH3+HCl=>CH3-CH2-CHCl-CH3</span>
M раствора = m соли + m воды
= 45+230= 275 г
w соли= m соли/ m раствора *100%=16,36%
27.6g 31g XL
K2CO3+2HCL-->2KCL+H2O+CO2↑
138 22.4
M(K2CO3)=138 g/mol
M(HCL)=36.5 g/mol
Vm=22.4 L/mol
n(K2CO3)=m/M=27.6 / 138=0.2 mol
n(HCL)=31/36.5=0.85 mol
n(K2CO3)<n(HCL)
27.6/138 = X/22.4
X=4.48 л
ответ 4.48 л, СО2