№2
в)x^2 +64=0
x^2 = - 64
/x/=√64
x= 8 x= - 8
Ответ: 8 ; - 8.
г) 3x^2 - 15=0
3x^2 = 15
x^2 = 5
/x/ = √5
x=√5 x= - √5
Ответ: √5 ; -√5
№3
x^2-3x-10=0
D=b^2 - 4ac = ( -3)^2 - 4 * 1 * ( - 10) = 9+40=49
√D=7
x1=3+7 / 2 = 5
x2= 3 - 7 / 2 = ⇒ - 2 - Является .
Ответ: 5; - 2
№4
![( \sqrt{5}- \sqrt{2})^2=( \sqrt{6})^2-2 \sqrt{5}* \sqrt{2}+( \sqrt{2})^2=5- 2\sqrt{10}+2=7+2 \sqrt{10}](https://tex.z-dn.net/?f=%28+%5Csqrt%7B5%7D-+%5Csqrt%7B2%7D%29%5E2%3D%28+%5Csqrt%7B6%7D%29%5E2-2+%5Csqrt%7B5%7D%2A+%5Csqrt%7B2%7D%2B%28+%5Csqrt%7B2%7D%29%5E2%3D5-+2%5Csqrt%7B10%7D%2B2%3D7%2B2+%5Csqrt%7B10%7D+)
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![(4- \sqrt{10})(4+ \sqrt{10})=(4^2-( \sqrt{10})^2)=16-10=6](https://tex.z-dn.net/?f=%284-+%5Csqrt%7B10%7D%29%284%2B+%5Csqrt%7B10%7D%29%3D%284%5E2-%28+%5Csqrt%7B10%7D%29%5E2%29%3D16-10%3D6)
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Вийде: х=-4
Дякую що поважаєте нас
Ответ:
Объяснение:
(2x^5 *y^7)³:(x^14 *y^20)-(3xy^5)³:(x²y^14)=8x^(5*3-14) *y^(7*3-20) -27x^(3-2) *y^(5*3-14)=8x^(15-14) *y^(21-20) -27x^1 *y^(15-14)=8x^1 *y^1 -27xy^1=-19xy
(-3a^4 *b^5)²*(-2a²b³)³:(-72a^6 *b^9)²+a²b=9a^(4*2) *b^(5*2) *(-8a^(2*3) *b^(5*2)):((-72)²a^(6*2) *b^(9*2))+a²b=(-72a^(8+6) *b^(10+10)):((-72)²a^12 *b^18)+a²b=-72^(1-2) *a^(14-12) *b^(20-18) +a²b=-1/72 *a²b²+a²b=a²b -(a²b²)/72
(5x^6 *y²)³*(-x^8 *y^7)²:(-0,2x^15 *y^10)²-10x^4=(5³x^(6*3+8*2) *y^(2*3+7*2)):(0,04x^(15*2) *y^(10*2))-10x^4=5³*25x^(18+16-30) *y^(6+14-20) -10x^4=5³*5²x^4 *y^0 -10x^4=5^(3+2) *x^4 *1-10x^4=5^5 x^4 -10x^4=3125x^4 -10x^4=3115x^4
(-2a^10 *b^20)²:(-a²b³)³:(-2a^5 *b^24)²=2^(2-2) *(-(a^(10*2-2*3-5*2))) *b^(20*2-3*3-24*2)=-2^0 *a^(2*(10-3-5)) *b^(40-9-48)=-1a^(2*2) *b^(-17)=-(a^4)/b^17
f`(x)=3*2sinx*cosx=3 sin(2x)
1) х^2 - 81=(x-9)(x+9)
2) 49 - у^2=(7-y)(7+y)
3) х^2 - 9/25=(x-3/5)(x+3/5)
<span>4) 0,09 - с^2=(0,3-c)(0,3+c)</span>