Решение во вложениииииииииииииииииии
![2 \sqrt{10}= \sqrt{2^2*10}= \sqrt{4*10}= \sqrt{40} \\\\6,5= \sqrt{6,5^2}= \sqrt{42,25} \\\\ \sqrt{41} \\\\ \sqrt{42,25} > \sqrt{41}> \sqrt{40} \\\\6,5> \sqrt{41}> 2\sqrt{10}](https://tex.z-dn.net/?f=2+%5Csqrt%7B10%7D%3D+%5Csqrt%7B2%5E2%2A10%7D%3D+%5Csqrt%7B4%2A10%7D%3D+%5Csqrt%7B40%7D++%5C%5C%5C%5C6%2C5%3D+%5Csqrt%7B6%2C5%5E2%7D%3D+%5Csqrt%7B42%2C25%7D+%5C%5C%5C%5C+%5Csqrt%7B41%7D+%5C%5C%5C%5C+%5Csqrt%7B42%2C25%7D+%3E+%5Csqrt%7B41%7D%3E+%5Csqrt%7B40%7D+%5C%5C%5C%5C6%2C5%3E+%5Csqrt%7B41%7D%3E+2%5Csqrt%7B10%7D++++++)
Ответ: 6,5; <span>√41; </span><span>2<span>√10</span></span>
4 8/10:6/7=48/10:6/7=48/10*7/6=56/10=5 6/10
2а(3а-5b) - 3a(2a-b) = 2a*3a +2a*(-5b) - 3a*2a -3a*(-b)=
= 6a² - 10ab -6a² + 3ab = (6a² -6a²) + (-10ab + 3ab)=
= - 7ab
-12b(1/4 - a) - 6a(2b - 1/3) =
= - 12b/4 - 12b * (-a) - 6a*2b - 6a/(-3) =
= - 3b + 12ab - 12ab + 2a =
= - 3b + 2a =
= 2a - 3b
при а= - 0,7 ; b=2
2*(-0,7) - 3*2 = - 1,4 - 6 = - (1,4 + 6,0) = - 7,4