= 2M*(1 - 2M) \ M - 3
/////////////////////////////////////
0.6X^2 - X - 0.4 = 0
D = 1 - 4*0.6 *(-0.4) = 1 + 0.96 = 1.96 V D = 1.4
X1 = 1 + 1.4 \ 1.2 = 2
X2 = 1 - 1.4 \ 1.2 = - 1\3
Надо и числитель , и знаменатель выразить через тангенс. Для этого и числитель и знаменатель разделим на Cosx
Cделаем по частям:
числитель= 4Sinx/Cos x - Cosx /Cosx = 4tg x -1 = 4*1/4 -1 = 1 - 1 = 0
знаменатель = Сosx/Cosx +4Sinx/Cosx = 1 + 4tgx = 1 + 4*1/4 = 1+1 = 2
сама дробь= 0/2=0
Ответ:
Объяснение:
5; 5/6; ... b₁=5 b₂=5/6
q=b₂/b₁=(5/6)/5=1/6.
b₄=b₁*q³=5*(1/6)³=5/216.
Sn=b₁*(qⁿ-1)/(q-1)
S₄=5*((1/6)⁴-1))/((1/6)-1)=5*((1/1296-1))/(-5/6)=
=-6*(-1295/1296)=1285/216=5²¹⁵/²¹⁶.
Ответ: q=1/6 b₄=5/216 S₄=5²¹⁵/₂₁₆.
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Определение:
![\lim_{dx \to 0} \frac{dy}{dx} = \lim_{dx \to0} \frac{f(x+dx)-f(x)}{dx}](https://tex.z-dn.net/?f=+%5Clim_%7Bdx+%5Cto+0%7D++%5Cfrac%7Bdy%7D%7Bdx%7D+%3D+%5Clim_%7Bdx+%5Cto0%7D++%5Cfrac%7Bf%28x%2Bdx%29-f%28x%29%7D%7Bdx%7D++)
нахождение производной:
у=х²+1
f(x)=x²+1
f(x+dx)=(<span>x+dx)</span>²+1=x²+2xdx+(dx)²+1
![\lim_{dx \to0} \frac{f(x+dx)-f(x)}{dx}=\lim_{dx \to0} \frac{x^2+2xdx+(dx)^2+1-(x^2+1)}{dx}= \\ \\ =\lim_{dx \to0} \frac{x^2+2xdx+(dx)^2+1-x^2-1)}{dx}= \lim_{dx \to0} \frac{2xdx+(dx)^2}{dx}= \\ \\ =\lim_{dx \to0} \frac{dx(2x+dx)}{dx}= \lim_{dx \to0} (2x+dx)=2x+0=2x](https://tex.z-dn.net/?f=%5Clim_%7Bdx+%5Cto0%7D+%5Cfrac%7Bf%28x%2Bdx%29-f%28x%29%7D%7Bdx%7D%3D%5Clim_%7Bdx+%5Cto0%7D+%5Cfrac%7Bx%5E2%2B2xdx%2B%28dx%29%5E2%2B1-%28x%5E2%2B1%29%7D%7Bdx%7D%3D+%5C%5C++%5C%5C+%3D%5Clim_%7Bdx+%5Cto0%7D+%5Cfrac%7Bx%5E2%2B2xdx%2B%28dx%29%5E2%2B1-x%5E2-1%29%7D%7Bdx%7D%3D++%5Clim_%7Bdx+%5Cto0%7D+%5Cfrac%7B2xdx%2B%28dx%29%5E2%7D%7Bdx%7D%3D++%5C%5C++%5C%5C+%3D%5Clim_%7Bdx+%5Cto0%7D+%5Cfrac%7Bdx%282x%2Bdx%29%7D%7Bdx%7D%3D+%5Clim_%7Bdx+%5Cto0%7D+%282x%2Bdx%29%3D2x%2B0%3D2x)