3а²в-ав²-а²в+2ав²=2а²в+ав²
(47,8+48,4)/(163-89)=96,2/74=1,3
Ответ: 1,3.
1) y'= 3^x * ln3 -2
2)y'=5^6x-1 * ln5*(6x-1)' +e^3x * (3x)' = 5^6x-1 * 6ln5 + 3e^3x
<span>3)y=log3*(x^2+2x+4)
y'= 1/[(x</span>²+2x+4)*ln3] *(2x+2)
<span>
4)y=ln*(x^2-3x)+cos3x
y'= 1/(x</span><span>²-3x) * (2x-3) -sin3x * 3</span>
<span>(х+7)(х-7)+2(х-24)=x^2-49+2x-48=x^2+2x-97</span>
(m+n)-(m-n)=2mn
m+n-m+n=2mn
(m+n)(n-m)=2nm
nm в квадрате=2nm
2nm=2nm