Question

m^6+m^4+m^2+1 сократить дробь ПОМОГИТЕ ПЛИЗ______________m^3+m^2+m+1

Answer 1

$\frac{m^6+m^4+m^2+1}{m^3+m^2+m+1}=\\\frac{m^4(m^2+1)+(m^2+1)}{m^2(m+1)+(m+1)}=\\\frac{(m^2+1)(m^4+1)}{(m^2+1)(m+1)}=\\\frac{m^4+1}{m+1}$

Answer 2

$\frac{m^6+m^4+m^2+1}{m^3+m^2+m+1}=\frac{m^4(m^2+1)+(m^2+1)}{m^2(m+1)+(m+1)}=\frac{(m^2+1)(m^4+1)}{(m+1)(m^2+1)}=\frac{m^4+1}{m+1}$

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