Question

2a+cosa+tga, ctga=1

Answer 1

$ctg(a)=1\\a=arcctg1\\a=\frac{\pi}{4}$


$(sina)^2+\sqrt{2}cosa+tga=(sin\frac{\pi}{4})^2+\sqrt{2}*cos\frac{\pi}{4}+tg\frac{\pi}{4}=\\=(\frac{\sqrt{2}}{2})^2+\sqrt{2}*\frac{\sqrt{2}}{2}+1=\frac{1}{2}+1+1=2.5$