Question

1
$2 \sqrt{128} - \sqrt{72}$
2.
$(3 \sqrt{2} + \sqrt{50} ) \times \sqrt{2}$
3.
$(6 - \sqrt{3} ) \times \sqrt{2}$

Answer 1

2√128 -√72 =2*√(2*64) - √(2*36)=2*8√2- 6√2=16√2-6√2= 10√2

(3√2+√50)*√2 = (3√2+√(2*25))*√2= (3√2+5√2)*√2=8√2 *√2=16

(6 - √3)*√2= 6√2- √6

Answer 2

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