1) 4sinx*cosx*sin2x =1 ;
2sin2x*sin2x =1 ;
sin²2x =1/2 ;
( 1 -cos4x) /2 =1/2 ;
1 -cos4x =1 ;
cos4x =0 ⇒ 4x =π/2 +π*K⇒ x =π/8 +(π/4)*k ; k∈Z.
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2) <span>tg x≤ 1 ;
</span> - π*k - π/2 ≤ x ≤ π/4 + π*k .
3) <span>√2sin3x=1 ;
sin 3x =1/</span>√2 ;
3x =(-1)^k*π/4 +2π*k ;
x =(-1)^k*π/12 +2π*k ; k ∈Z ..
4) <span>sin3x=sin5x ;
</span>sin5x - sin3x =0 ;
2sin(5x - 3x)/2 *cos(5x + 3x)/2 =0 ;
2sinx *cos4x =0 ;
[ sinx =0 ; cos4x =0⇒[x =π*k ; 4x= π/2+π*k .
[x =π*k ; x= π/8+π/4*k ;k ∈Z .
(-10)²=100
0,7*100=70
70-20=50
1
(ab+ac)²/(ab²-ac²)=a²(b+c)/a(b²-c²)=a(b+c)/(b-c)(b+c)=a/(b-c)
2
1)1/c-1/(10-c)=(10-c-c)/c(10-c)=(10-2c)/c(10-c)=2(5-c)/c(10-c)=2(c-5)/c(c-10)
2)25/(c-5) -(c-5)=(25-c²+10c-25)/(c-5)=(10c-c²)/(c-5)=c(10-c)/(c-5)
3)2(c-5)/c(c-10) * c(10-c)/(c-5)=-2
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