![y=6x-4x^2,\; \; \; \; y=b-2x\\\\6x-4x^2=b-2x\\\\4x^2-8x+b=0\\\\D=64-16b=16(4-b)=0,\\\\b=4\\\\y=4-2x\; \; -\; kasatelnaya\\\\4x^2-8x+4=0|:4\\\\x^2-2x+1=0\\\\(x-2)^2=0,\; \; \to \; \; x=1\\\\y(1)=4-2\cdot 1=2](https://tex.z-dn.net/?f=y%3D6x-4x%5E2%2C%5C%3B+%5C%3B+%5C%3B+%5C%3B+y%3Db-2x%5C%5C%5C%5C6x-4x%5E2%3Db-2x%5C%5C%5C%5C4x%5E2-8x%2Bb%3D0%5C%5C%5C%5CD%3D64-16b%3D16%284-b%29%3D0%2C%5C%5C%5C%5Cb%3D4%5C%5C%5C%5Cy%3D4-2x%5C%3B+%5C%3B+-%5C%3B+kasatelnaya%5C%5C%5C%5C4x%5E2-8x%2B4%3D0%7C%3A4%5C%5C%5C%5Cx%5E2-2x%2B1%3D0%5C%5C%5C%5C%28x-2%29%5E2%3D0%2C%5C%3B+%5C%3B+%5Cto+%5C%3B+%5C%3B+x%3D1%5C%5C%5C%5Cy%281%29%3D4-2%5Ccdot+1%3D2)
Для проверки, чтто это точка касания, подставим х=1 во второе уравнение и убедимся, что это будет та же точка:
![y(1)=6\cdot 1=4\cdot 1^2=6-4=2](https://tex.z-dn.net/?f=y%281%29%3D6%5Ccdot+1%3D4%5Ccdot+1%5E2%3D6-4%3D2)
<span>3x^2+x=0</span>
x(3x+1)=0
x=0 или 3x+1=0
3x=-1
x=-1/3
Ответ:0;-1/3
Log3 (45/5) + 3^(2log3 5) = log3 (9) + 3^(log3 5^2) =
= 2 + 3^(log3 25) = 2 + 25 = 27
1)116/9×1/4+2/3×1/24=24/9+1/36=96+1/36=97/36
2)(9+14/36)×24/23-1=23/36×24/23-1=2/3-1=-1/3
3)5-(30+20+15+12/60)=5-77/60=300-77/60=223/60
4)16/11×11/12-10/9×6/5-54/7=4/3-4/3-54/7=-54/7
5)(24/7×21/8-16)×4/21+176/15=-7×4/21+176/15=-3/4+176/15=659/60