Question

Решить уравнение =

Answer 1

$2^{x^2 - 3} = 4^{x} \\ \\ 2^{x^2 - 3} = 2^{2x} \\ \\ x^2 - 3 = 2x \\ \\ x^2 - 2x - 3 = 0 \\ \\ x^2 - 2x + 1 - 4 = 0 \\ \\ (x - 1)^2 - 2^2 = 0 \\ \\ (x - 1 - 2)(x - 1 + 2) = 0 \\ \\ x = -3 \ \ \ \ \ \ x = -1$

Answer 2

$2^{x^2-3}=4^x \\ 2^{x^2-3}=2 ^{2x} \\ x^2-3=2x \\ x^2-3-2x=0 \\ x^2-2x-3=0 \\ D_{1} =(- \frac{b}{2} )^2-ac \\ D_{1}=4 \\ x= \frac{- \frac{b}{2}+- \sqrt{D} }{a} \\ x=-1 x=3$