![\frac{(2021*2001+(5*2)^2)(1971*2051+1600)^3}{2011^8}=1](https://tex.z-dn.net/?f=%5Cfrac%7B%282021%2A2001%2B%285%2A2%29%5E2%29%281971%2A2051%2B1600%29%5E3%7D%7B2011%5E8%7D%3D1)
Решаем по действиям с использованием формулы разности квадратов: (a-b)·(a+b) = a² - b²
1)
![2021*2001+(5*2)^2 =](https://tex.z-dn.net/?f=2021%2A2001%2B%285%2A2%29%5E2+%3D)
![=(2011-10)*(2011+10)+10^2=](https://tex.z-dn.net/?f=%3D%282011-10%29%2A%282011%2B10%29%2B10%5E2%3D)
![=2011^2-10^2+10^2=2011^2](https://tex.z-dn.net/?f=%3D2011%5E2-10%5E2%2B10%5E2%3D2011%5E2)
2)
![(1971*2051+1600)^3=](https://tex.z-dn.net/?f=%281971%2A2051%2B1600%29%5E3%3D)
![=((2011+40)*(2011-40)+1600)^3=](https://tex.z-dn.net/?f=%3D%28%282011%2B40%29%2A%282011-40%29%2B1600%29%5E3%3D)
![=(2011^2-40^2+1600)^3=](https://tex.z-dn.net/?f=%3D%282011%5E2-40%5E2%2B1600%29%5E3%3D)
![=(2011^2-1600+1600)^3=](https://tex.z-dn.net/?f=%3D%282011%5E2-1600%2B1600%29%5E3%3D)
![=(2011^2)^3=2011^6](https://tex.z-dn.net/?f=%3D%282011%5E2%29%5E3%3D2011%5E6)
3)
![\frac{2011^2*2011^6}{2011^8}=\frac{2011^{2+6}}{2011^8}=\frac{2011^{8}}{2011^8}=1](https://tex.z-dn.net/?f=%5Cfrac%7B2011%5E2%2A2011%5E6%7D%7B2011%5E8%7D%3D%5Cfrac%7B2011%5E%7B2%2B6%7D%7D%7B2011%5E8%7D%3D%5Cfrac%7B2011%5E%7B8%7D%7D%7B2011%5E8%7D%3D1)
А) 3/7 + 5/14 = 6/14 + 5/14 = 11/14
б) 8/9 - 7/12 = 32/36 - 21/36 = 11/36
в) 11/50 - 3/25 + 1/20 = 22/100 - 12/100 + 5/100 = 15/100 = 3/20 = 0,15
arcsin(sin257')<span>=-0.610597594 </span>
Если выражение равно нулю,то 2х-3+3х-2=0
5х-5=0
5(х-1)=0
х=1
Ответ: -4/3*c^2*d^33
Объяснение: переставим числа: -32c^15/24c^13 = -4/3*c^2
(d^4)^5*d^13 = (d^20)*d^13=d^33
Итого -4/3*c^2*d^33