<span>x^3-8y^3-6x^2y+12xy^2=<span>-(2y-x)^3</span></span>
<span>8x^6+y^3+12x^4y+6x^2y^2=<span>(y+2x^2)^3</span></span>
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2х-3у=-12
х+у=1
2х=3у-12
х=1,5у-6
1,5у-6+у=1
2,5у=7
у=7:2,5
у=2,8
х=1,5у-6
х=1,5*2,8-6
х=-1,8
Ответ:(-1,8;2,8)