(9a+18)-(2b+ab)+(2b²+ab²)=9(a+2)-b(2+a)+b²(2+a)=(a+2)(9-b+b²)
-х²+2х+3=3
-х²+2х=0
-х(х-2)=0
х=0 и х=2
Ответ:..........................
Log(a)b=log(c)b/log(c)a
log(a^n)(b^n)=log(a)b
nlog(a)b=log(a)b^n
-------------------------------------------------
a)
log(6)4+log(6)9+1/log(6)4 *2log(6)2 +2=log(6)(4*9)+log(6)4/log(6)4+2=
=log(6)36+1+2=2+3=5
б)
log(2)10+log(2)12-log(2)30 +4=log(2)(10*12/30)+4=log(2)4+4=2+4=6
в)
log(2)6+log(2)10-log(2)15+2^log(2)5=log(2)(6*10/15)+5=log(2)4+5=2+5=7