Question

Выполните деление: (6a^3-3a^2):a^2+(12a^2+9a):(3a)

Answer 1

(6a³-3a²):a²+(12a²+9a):(3a) = 
= 6а - 3 + 4а + 3 = 10а

Answer 2

$(6a^3-3a^2):a^2+(12a^2+9a):(3a) \\ \\ \frac{6a^3-3a^2}{a^2} + \frac{12a^2+9a}{3a} = \frac{a^2(6a-3)}{a^2} + \frac{3a(4a+3)}{3a} =6a-3+4a+3=10a$